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23 September, 14:36

What is the pH of a 40.0 40.0 mL solution that is 0.11 0.11 M in CN - CN - and 0.21 0.21 M in HCN HCN? The K a Ka for HCN is 4.9 * 10 - 9

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  1. 23 September, 16:49
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    pH=8.03

    Explanation:

    From the Henderson-Hasselbalch equation:

    we know that

    pH = pKa + log (base / acid)

    plugging the values from the question we can write

    pH = 8.31 + log (0.11 / 0.21)

    pH = 8.31-0.280

    pH=8.03
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