Calculate the Molarity (M) of an aqueous solution of HCl which is 35.38% HCl by mass and has a density of 1.161 g/mL.

11.2 M → [HCl]

Explanation:

Solution density = Solution mass / Solution volume

35.38 % by mass, is the same to say 35.38 g of solute in 100 g of solution.

Let's determine the moles of our solute, HCl

35.38 g. 1 mol/36.45 g = 0.970 moles

Let's replace the data in solution density formula

1.161 g/mL = 100 g / Solution volume

Solution volume = 100 g / 1.161 g/mL → 86.1 mL

Let's convert the volume to L → 86.1 mL. 1L / 1000 mL = 0.0861 L

Molarity (M) → mol/L = 0.970 mol / 0.0861 L → 11.2 M