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24. The standard free energy of the aldolase reaction (in the reverse aldol direction) is 23.8 kJ/mol. The concentrations of the three metabolites in the hepatocyte are: fructose 1,6-bisphosphate (1.4 X 10-5 M), glyceraldehyde 3-phosphate (3 X 10-6 M) and dihydroxyacetone phosphate (1.6 x 10-5 M). Calculate the actual free energy of the reaction at 37 degrees C.

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  1. Today, 13:40
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    The actual free energy = 78.54 X 10⁻² J

    Explanation:

    Given standard free energy = 23.8 kJ/mol

    Free energy due to the presence of fructose 1,6-bisphosphate (1.4 X 10⁻⁵ M)

    = 1.4 X 10⁻⁵ M * (23800 J/mol)

    = 33.32 X 10⁻² J

    Free energy due to the presence of glyceraldehyde 3-phosphate (3 X 10⁻⁶ M)

    = 3 X 10⁻⁶ M * (23800 J/mol)

    =7.14 X 10⁻² J

    Free energy due to the presence of dihydroxyacetone phosphate (1.6 x 10⁻⁵M)

    = 1.6 x 10⁻⁵M * (23800 J/mol)

    = 38.08 X 10⁻² J

    The actual free = 33.32 X 10⁻² J + 7.14 X 10⁻² J + 38.08 X 10⁻² J

    The actual free energy = 78.54 X 10⁻² J
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