A 2.50-kg steel gasoline can hold 20.0 L of gasoline when full.

What is the average density of the full gas can, taking into account the volume occupied by steel as well as by gasoline?

805 kg/m^3.

Explanation:

Okay, in the question above we are given the following parameters; the mass of steel gasoline = 2.50-kg, volume of gasoline it can hold = 20.0 L. Then we are asked to calculate the average density of the full can.

Recall that the formula for Calculating density = mass / volume.

So, the total mass of the full can = mass of the steel can, m1 + mass of the gasoline, m2.

Although, we are not given but the density of gasoline = 0.68 g/cm^3 or 6.7 * 10^2 kg/m^3. (Note that you can use any of the value for density of gasoline just take note of the units, for instance one is in g/cm^3 and the other is in kg/m^3). For instance, if we take the one in g/cm^3 we have;

The mass of gasoline = 0.68 * (10^3 * 20).

Mass of gasoline = 13.6 * 10^3 g or 13.6 kg.

Since the mass in the question is given to us In kilograms we will be using the kg unit.

Therefore, the total mass of the full can = mass of the steel can, m1 + mass of the gasoline, m2.

===>2.50 + 13.6.

Then, going back to the formula for Calculating density, we have;

Average density = 2.50 + 13.6 / 20 * 10^3.

Average density = 805 kg/m^3.