Ask Question
3 July, 22:10

A 1.00 L flask containing gas A at 5.00 atm is connected to a 4.00 L flask containing gas B at 1.00 atm. When the two gases are allowed to mix at constant temperature, what is the final pressure in the two-flask assemblage?

+1
Answers (1)
  1. 3 July, 23:38
    0
    The final pressure in the two-flask assemblage is 1.8 atm

    Explanation:

    The given variables are

    Flask 1 with gas A = 1.00 L at 5.00 atm

    Flask 2 with gas B = 4.00 L at 1.00 atm

    From the Daltons law of partial pressure which states that the total pressure of a given mixture of gases is equal to the sum of the partial pressures of the gases in the mixture

    Ptotal = P₁ + P₂ + P₃

    Final volume of both gases = 5.00 L

    Boyle's law states that the pressure of a given mass of gas is inversely proportional to its volume

    P₁·V₁ = P₂·V₂

    Therefore their final pressure =

    for gas A 1.00 L * 5.00 atm = 5.00 L * P₂

    therefore P₂ = 1.00 atm

    for gas B

    1.00 atm * 4.00 L = P₂*5.00 L

    Therefore P₂ = 4/5 atm

    Total pressure P₂ for gas A + P₂ for gas B

    1+4/5 atm or 1.8 atm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 1.00 L flask containing gas A at 5.00 atm is connected to a 4.00 L flask containing gas B at 1.00 atm. When the two gases are allowed to ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers