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19 April, 21:38

Vinegar is a solution of acetic acid, CH3COOH, dissolved in water. A 5.54-g sample of vinegar was neutralized by 30.10 mL of 0.100 M NaOH. What is the percent by weight of acetic acid in the vinegar?

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  1. 19 April, 21:47
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    3.26 % of vinegar is acetic acid

    Explanation:

    Step 1: Data given

    Mass of the sample = 5.54 grams

    Volume of NaOH = 30.10 mL

    Molarity of NaOH = 0.100M

    Step 2: The balanced equation

    CH3COOH + NaOH → CH3COONa + H2O

    Step 3: Calculate moles NaOH

    Moles NaOH = volume * molarity

    Moles NaOH = 0.03010 L * 0.100M

    Moles NaOH = 0.00301 moles NaOH

    Step 4: Calculate moles CH3COOH

    For 1 mol NaOH we need 1 mol CH3COOH

    For 0.00301 moles NaOH we nee 0.00301 moles CH3COOH

    Step 5: Calculate mass CH3COOH

    Mass CH3COOH = moles CH3COOH * molar mass CH3COOH

    Mass CH3COOH = 0.00301 moles * 60.05 g/mol

    Mass CH3COOH = 0.1808 grams

    Step 6: Calculate percent by weight of acetic acid

    Mass % = (0.1808 / 5.54) * 100%

    Mass % = 3.26 %

    3.26 % of vinegar is acetic acid
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