Calculate the standard reaction free energy of the following chemical reaction:

2Al (s) + Fe2O3 (s) → Al2O3 (s) + 2Fe (s)

The question is incomplete, the complete question is:

Calculate the standard enthalpy change for a reaction? : Fe2O3 (s) + 2Al (s) = Al2O3 (s) + 2Fe (s).

The standard enthalpies of formation of Fe2O3 and Al2O3 are

-822 and - 1669 KJ mol-1 respectively. State whether the reaction is exothermic or

endothermic

Answer:

∆H°reaction = - 847KJmol-1

Explanation:

Recall that ∆H°element = 0KJ mol-1

Therefore

∆H°reaction = ∆H°products - ∆H°reactants

= (-1669) - (-822) = - 847KJmol-1

The reaction is exothermic as ∆H°reaction is negative.