Ask Question
20 December, 10:03

What is the number of molecules in 19.5 L of nitrogen gas at STP

+5
Answers (1)
  1. 20 December, 13:38
    0
    5.24*10²³ molecules of N₂ are in 19.5L of gas

    Explanation:

    In order to find out the number of molecules, we need to know the mass of N₂ and we must use density of N₂ for that propose

    N₂ density = N₂ mass / N₂ volume

    N₂ density. N₂ volume = N₂ mass → 1.25 g/L. 19.5 L = 24.4 g

    Molar mass N₂ = 28 g/mol → 1 means that 1 mol of N₂ weighs 28 g, so as 1 mol is 28 g and 1 mol contains 6.02*10²³ molecules, 6.02*10²³ molecules are contained in 28 g. Let's make a rule of three, for this:

    28 g of N ₂ contain 6.02*10²³ molecules

    Then, 24.4 g of N₂ may contain (24.4. 6.02*10²³) / 28 = 5.24*10²³ molecules
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What is the number of molecules in 19.5 L of nitrogen gas at STP ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers