A 22.25 g piece of metal is dropped into a graduated cylinder with 126.3 mL of water. If the density of the metal is 4.43 g/cm3, what is the total volume in the graduated cylinder in mL with the correct number of significant digits?

131.2 mL would be the total volume in the graduated cylinder.

Explanation:

Let's work with the density of metal to find out its volume

Metal density = Metal mass / metal volume

4.46 g/mL = 22.25 g / metal volume

Metal volume = 22.25 g / 4.46 g/mL = 4.98 mL

If we suppose aditive volume, total volume in the graduated cylinder will be:

126.3mL + 4.9mL = 131.2 mL