A student wishes to prepare 2.00 liters of 0.100-molar KIO3 (molecular weight 214). The proper procedure is to weigh out.

The mass of KIO3 is 42.8 grams

Explanation:

Step 1: Data given

Volume = 2.00 L

Molarity = 0.100 molar

Molar mass of KIO3 = 214 g/mol

Step 2: Calculate moles

Moles = Molarity * volume

Moles = 0.100 M * 2.00 L

Moles = 0.200 moles

Step 3: Calculate mass of KIO3

Mass KIO3 = moles KIO3 * molar mass KIO3

Mass KIO3 = 0.200 moles * 214 g/mol

Mass KIO3 = 42.8 grams

The mass of KIO3 is 42.8 grams

weight = 42.8 g

Explanation:

given data

volume = 2 liters

molarity = 0.100

KIO3 molecular weight = 214

to find out

weigh out

solution

we know that Molarity that is express as to get mole

molarity = Mol of solute : solution volume ... 1

put here value we get

Mol of solute = 0.100 * 2

Mol of solute = 0.2

and

mol is express as

Mol = Weight : Molecular weight ... 2

put here value

weight = 0.2 * 214

so weight = 42.8 g