If the latent heat of fusion for water is 333.4 J/g, how much heat is required to melt 170 grams of ice at 0 °C?

56.7 KJ

Explanation:

Data Given:

latent heat of fusion for water (Lf) = 333.4 J/g

amount of ice (mass) = 170 gram

heat required to melt ice (Q) = ?

Solution:

Latent heat of fusion: the amount of heat that required to melt certain amount of a substance. The total heat absorbed by substance is proportional to the total heat of fusion of the material.

Formula Used

Q = mLf

Q = heat required to melt a substance

m = mass of the substance

Lf = latent heat of fusion also denoted by ΔHf

put values in above formula

Q = mLf

Q = 170 g x 333.4 J/g

Q = 56678 J

convert J to KJ

1000 J = 1 KJ

56678 J = 56678 / 1000 = 56.678 KJ

Q ≅ 56.7 KJ