A balloon is filled with 35.0 L of helium in the morning when the temperature is 303 degrees kelvin. By 3:00 p. m., the temperature has risen to 333 degrees kelvin. What is the new volume of the balloon?

2882 L

38.5 L

31.8 L

65.0 L

38.5 L

Explanation:

For this question, we can use

V1/T1=V2/T2

where

V1 (initial volume) = 35 L

T1 (initial temperature in Kelvin) = 303 K

V2 (final volume) = ?

T2 (final temperature in Kelvin) = 333K

Since we are trying to find the final volume, we can rearrange the equation to say

V2 = (V1/T1) * T2

V2 = (35/303) * 333

V2 = 38.5 L