Find the temperature (°C) of 1.25 moles of a gas if the gas has a volume 20.0 liters at a pressure of

1.75 atm.

T = 66.66 °C

Explanation:

Given dа ta:

Moles of gas = 1.25 mol

Volume of gas = 20.0 L

Pressure of gas = 1.75 atm.

Temperature of gas = ?

Solution:

PV = nRT

T = PV / nR

T = 1.75 atm * 20 L / 1.25 mol * 0.0821 atm. L. mol⁻¹. K⁻¹

T = 35 atm. L / 0.103 atm. L. K⁻¹

T = 339.81 K

T = 339.81 K - 273.15 = 66.66 °C