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18 February, 20:41

If you combine 25.0 gg of a solute that has a molar mass of 25.0 g/molg/mol with 100.0 gg of a solvent, what is the molality of the resulting solution?

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  1. 18 February, 21:34
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    10 mol/kg.

    Explanation:

    Molality can be defined as the number of moles of solute divided by the mass of solvent.

    Number of moles = mass/molar mass

    = 25/25

    = 1 mol.

    Mass of solvent in kg = 100 g * 1 kg/1000 g

    = 0.1 kg

    Molality, m = 1/0.1

    = 10 mol/kg.
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