4Fe + 3O2 → 2Fe2O3

Iron combines with oxygen to form rust. Given the chemical reaction, how many grams of 4Fe + 3O2 would produce 10 g of rust?

A) 7 g

B) 10 g

C) 30 g

D) 70 g

Question

Chemistry

Keenan Leonard

24 March, 12:58

4Fe + 3O2 → 2Fe2O3

Iron combines with oxygen to form rust. Given the chemical reaction, how many grams of 4Fe + 3O2 would produce 10 g of rust?

A) 7 g

B) 10 g

C) 30 g

D) 70 g

+1

Answers (2)

Know the Answer?

Catherine Mcintyre · Answer 1

n (2Fe2O3) = 10g/319.374amu=0.03mol

n (4Fe+3O2) = 0.03 mol

m (4Fe+2O2) = Mn=319.374*0.03=9.58=10

Jaylyn Reilly · Answer 2

b) 10 g

Explanation:

Hi, the answer in simply: during a chemical reaction (that doesn't involve nuclear processes) the total mass involved is constant.

The total mass of the reactants equals the total mass of the products, althought the number of molecules may vary.

4Fe + 3O2 → 2Fe2O3Iron combines with oxygen to form rust. Given the chemical reaction, how many grams of 4Fe + 3O2 would produce 10 g of rust?A) 7 gB) 10 gC) 30 gD) 70 g

4Fe + 3O2 → 2Fe2O3

Iron combines with oxygen to form rust. Given the chemical reaction, how many grams of 4Fe + 3O2 would produce 10 g of rust?

A) 7 g

B) 10 g

C) 30 g

D) 70 g