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11 December, 15:13

A 2.25-L container filled with CO2 gas at 25∘C and 225 kPa pressure springs a leak. When the container is re-sealed, the pressure is 185 kPa and the temperature is 10 ∘C. How many moles of gas were lost?

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  1. 11 December, 18:15
    0
    0.001mol

    Explanation:

    First let us determine the new volume

    P1 = 225kpa

    V1 = 2.25L

    T1 = 25°C = 25 + 273 = 298k

    P2 = 185 kPa

    T2 = 10°C = 10 + 273 = 283k

    V2 = ?

    P1V1/T1 = P2V2/T2

    225x2.25/298 = 185xV2/283

    298x185xV2 = 225x2.25x283

    V2 = (225x2.25x283) / (298x185)

    V2 = 2.6L

    Now let us find the number of mole at each state

    State 1:

    V = 2.25L

    P = 225kpa = 225000Pa we must covert this to atm

    101325Pa = 1atm

    225000Pa = 225000/101325 = 2.22atm

    T = 25°C = 25 + 273 = 298k

    R = 0.082atm. L/mol/K

    n = ?

    PV = nRT

    n = PV/RT

    n = 2.25x2.22/0.082x298

    n = 0.204mol

    State 2:

    V = 2.6L

    P = 185 kPa = 185000Pa we must covert this to atm

    101325Pa = 1atm

    185000Pa = 185000/101325 = 1.83atm

    T = 10°C = 10 + 273 = 283k

    R = 0.082atm. L/mol / k

    n = ?

    PV = nRT

    n = PV/RT

    n = 1.83x2.6/0.082x283

    n = 0.205mol

    Change in number of mole

    = 0.205 - 0.204 = 0.001mol
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