If you burn 22.4 22.4 g of hydrogen and produce 2.00 * 10 2 2.00*102 g of water, how much oxygen reacted?

179.2g of O2

Explanation:

Fir, we must obtain a balanced equation for the reaction.

The equation for the reaction is:

2H2 + 02 - > 2H2O

Next, we find the molar mass of H2 and O2 as shown below:

Molar Mass of H2 = 2x1 = 2g/mol

Mass conc. of H2 from the balanced equation = 2 x 2 = 4g

Molar Mass of O2 = 16x2 = 32g/mol

From the equation,

4g of H2 required 32g of O2,

Therefore 22.4g of H2 will require = (22.4x32) / 4 = 179.2g of O2