The volume of a gas is 4.0 L when the pressure is 1.00 atm. At the same temperature, what is the pressure at which the volume of the gas is 2.0 L?

Answer: 2.00 atm

Explanation:

The gas is kept under the same temperature in this problem. Assuming the amount of gas is constant, we can apply the Boyle's law.

The Boyle's law equation,

P₁V₁ = P₂V ₂

Plug in the values,

1.00 atm x 4.0 L = P₂ x 2.0 L

Simplify,

4.00 atm L = 2 P₂ L

Now flip the equation,

2 P₂ L = 4.00 atm L

Dividing both sides by 2 we get,

P₂ = 2.00 atm