5. A gas collected when the temperature is 298K and the pressure is 1.25 atm has a volume of 0.254L. Calculate the volume when the temperature is lowered to 278K and the pressure is 1.67 atm. Assume number of gas particles remain constant.

asked V2

0.177L

Explanation:

For this, we can use the combined gas law

(P1*V1) / T1 = (P2*V2) / T2

where

P1 (initial pressure) = 1.25 atm

V1 (initial volume) = 0.254L

T1 (initial temperature in Kelvin) = 298K

P2 (final pressure) = 1.67 atm

V2 (final volume) = ?

T2 (final temperature in Kelvin) = 278K

Since we are trying to find the final volume, we can rearrange the above equation to make V2 the subject.

V2 = (((P1*V1) / T1) * T2) / P2

V2 = (((1.25*0.254) / 298) * 278) / 1.67

V2=0.17736004501

V2 = 0.177L