A beaker contains 249 mL of a 6.54 M HCl (aq) solution. Determine the new concentration of the solution after it is diluted by adding 167 mL of water to the beaker. Express the concentration in molarity to three significant figures.

The new molarity is 0.614 M

Explanation:

Formula for dilutions is:

M concentrated. Volume of conc = Volume of dil. M diluted

6.54 M. 249 mL = 416 mL. M diluted

Notice that volume of diluted is = Initial volume + What we added of water

(249mL + 167 mL)

(6.54 M. 249 mL) / 416mL = M diluted → 0.614 M