Ask Question
18 October, 22:48

5.00 g of an unknown compound was dissolved in 250.0 mL of water. The unknown compound was found to be a non-electrolyte and the osmotic pressure of the solution was determined to 14.5 atm at 298 K. Calculate the molar mass of the unknown compound (in units of g/mol). R = 0.08206 (L atm) / (mol K)

+3
Answers (1)
  1. 19 October, 02:36
    0
    This unknown compound has a molar mass of 33.74g/mole

    Explanation:

    Step 1: Given data

    The formula for the osmotic pressure is:

    π = MRT = 14.5 atm

    ⇒ with M = Concentration of the solution

    ⇒ with R = gas constant = 0.08206 L atm / mol K

    ⇒ with T = absolute temperature (in Kelvin) = 298K

    Step 2: Calculate concentration

    M = π / RT

    M = 14.5 / (0.08206 * 298)

    M = 0.593 M this is 0.593 moles per L

    Step 3: Calculate number of moles

    Since the volume is only 0.250 L, the amount of moles is:

    0.593 * 0.250 L = 0.1482 moles

    Step 4: Calculate molar mass

    The molar mass is : mass / moles

    Molar mass of this unknown compund = 5g / 0.1482 moles = 33.74 g/mole

    This unknown compound has a molar mass of 33.74g / mole
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “5.00 g of an unknown compound was dissolved in 250.0 mL of water. The unknown compound was found to be a non-electrolyte and the osmotic ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers