What is the mole fraction of 25.0 g of ethanol (c2h5oh) is added to 75.0 g of water to form 96.4 mL of solution

0.116

Explanation:

The molar mass of ethanol is 46.07 g/mol. The moles corresponding to 25.0 g are:

25.0 g * (1 mol/46.07 g) = 0.543 mol

The molar mass of water is 18.02 g/mol. The moles corresponding to 75.0 g are:

75.0 g * (1 mol/18.02 g) = 4.16 mol

The total number of moles is:

total moles = mol ethanol + mol water = 0.543 mol + 4. 16 mol = 4.70 mol

The mole fraction of ethanol is:

X (Ethanol) = mol ethanol / total moles = 0.543 mol / 4.70 mol = 0.116