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27 March, 20:41

Calculate the pH of the solution:

[OH-] = 1 x 10^-11M

a

12.0

b

2.7

c

3.0

d

11.0

+1
Answers (1)
  1. 27 March, 22:30
    0
    c. 3.0

    Explanation:

    pOH = - log[OH-]

    pOH = - log[1 x 10^-11 M

    pOH = 11

    pH + pOH = 14

    pH + 11 = 14

    pH = 14 - 11

    pH = 3

    c. 3.0
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