Calculate the heat released when 25.0 grams of water freezes at 0 degree Celsius.

= 8350 joules

Solution and explanation:

The heat of fusion refers to the quantity of heat released when a given amount of water freezes. For example, 1 g of water releases 334 J when it freezes at 0°C.

Therefore; For 25.0 g of water.

Heat released = Mass of water * heat of fusion

= 25 g * 334 J/g

= 8350 Joules

Hence, the amount of heat released when 25.0 g of water freezes at 0°C is 8350 J.