How much mass of iodine would react with 48 grams of magnesium to make magnesium iodide?

Mg + I2 - > MgI2

Mass = 507.6 g

Explanation:

Given dа ta:

Mass of Mg = 48 g

Mass of iodine react = ?

Solution:

Chemical equation:

Mg + I₂ → MgI₂

Now we will determine the number of moles of Mg.

Number of moles = mass / molar mass

Number of moles = 48 g / 24 g/mol

Number of moles = 2 mol

Now we will compare the moles of Mg with iodine.

Mg : I₂

1 : 1

2 : 2

Mass of iodine:

Mass = number of moles * molar mass

Mass = 2 mol * 253.8 g/mol

Mass = 507.6 g