Calculate the pressure, in atmospheres, of 2.0 mol of helium gas in a 10.0 L container at 27 degrees Celsius.

4.92atm

Explanation:

From the question, the following were obtained:

V = 10L

T = 27°C = 27 + 273 = 300K

n = 2moles

R = 0.082atm. L/K / mol

P = ?

Using the ideal gas equation PV = nRT, we can solve for the pressure as follows:

PV = nRT

P = nRT / V

P = (2x0.082x300) / 10

P = 4.92atm