The enzyme urease enhances the rate of urea hydrolysis at pH 8.0 and 20C by a factor of 1014. If a given quantity of urease can completely hydrolyze a given quantity of urea in 5.0 min at 20 C and pH 8.0, how long would it take for this amount of urea to be hydrolyzed under the same conditions in the absence of urease? Assume that both reactions take place in sterile systems so that bacteria cannot attack the urea.

Question

Chemistry

Dayana

1 May, 16:16

The enzyme urease enhances the rate of urea hydrolysis at pH 8.0 and 20C by a factor of 1014. If a given quantity of urease can completely hydrolyze a given quantity of urea in 5.0 min at 20 C and pH 8.0, how long would it take for this amount of urea to be hydrolyzed under the same conditions in the absence of urease? Assume that both reactions take place in sterile systems so that bacteria cannot attack the urea.

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Ernesto Skinner · Answer 1

It will take 950 million years for this amount of urea to be hydrolyzed under the same conditions in the absence of urease.

Explanation:

Given that:

In the presence of urease:

Urease enhances the rate of hydrolysis by = 10^14

Time taken in hydrolysis is 5 min

In the absence of urease:

Time taken in hydrolysis will be = 5 min x 10^14

Now, converting minutes into years

Time = (5 min x 10^14) / (60 min/hr x 24 hr/day x 365 days/year)

Time = 9.50 x 10^8 years

Time = 950 X 10^6 years

Time = 950 million years