30) How many grams of CH3OH must be added to water to prepare 210 mL of a solution that is

1.50 M CH3OH?

A) 10.0g

B) 48.0 g

C) 3.20 g

D) 0.210 g

E) 22.08

Mass = 10.0 g

Explanation:

Given dа ta:

Molarity = 1.50 M

Volume = 210 mL (0.21 L)

Grams of CH₃OH = ?

Solution:

Number of mole = molarity * volume

Number of mole = 1.50 M * 0.21 L

Number of mole = 0.315 mol

Mass of CH₃OH:

Mass = Number of moles * molar mass

Mass = 0.315 mol * 32.04 g/mol

Mass = 10.0 g