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1 June, 08:32

You need a 35% alcohol solution. On hand, you have a 280 mL of a 30% alcohol mixture. You also have 75% alcohol mixture. How much of the 75% mixture will you need to add to obtain the desired solution

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  1. 1 June, 11:04
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    35 mL

    Explanation:

    Let the amount of 75% mixture needed be A.

    The amount of each solution with their respective concentration to be added together can be expressed as:

    0.75A + 0.3 (280) ... eqn 1

    The addition of the two solution must merge with the expected concentration and this can be expressed as:

    0.35 (A + 280) ... eqn 2

    Eqn 1 must be equal to eqn 2, hence:

    0.75A + 0.3 (280) = 0.35 (A + 280)

    Solve for A.

    0.75A + 84 = 0.35A + 98

    0.40A = 14

    A = 35

    Hence, 35 mL of the 75% mixture will be needed.
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