What is the limiting reagent when 3.1 mol of SO2 react with 2.7 mol of O2

according to the equation: 2SO2 (g) + O2 (g) - -> 2SO3 (g)

The number of moles of SO₃ produced by SO₂ are less so it is limiting reactant.

Explanation:

Given dа ta:

Number of moles of SO₂ = 3.1 mol

Number of moles of O₂ = 2.7 mol

Limiting reactant = ?

Solution:

Chemical equation;

2SO₂ + O₂ → 2SO₃

Now we will compare the moles of SO₃ with O₂ and SO₂.

SO₂ : SO₃

2 : 2

3.1 : 3.1

O₂ : SO₃

1 : 2

2.7 : 2*2.7 = 5.4 mol

The number of moles of SO₃ produced by SO₂ are less so it is limiting reactant.