For the oxidation of glucose (CH 206 + 602 61,0 + 6CO2), how many grams of

oxygen gas will be consumed when 950 g of glucose is oxidized completely?

Mass = 1017.6 g

Explanation:

Given dа ta:

Mass of glucose = 950 g

Mass of oxygen needed = ?

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 950 g / 180 g/mol

Number of moles = 5.3 mol

Now we will compare the moles of oxygen and glucose.

C₆H₁₂O₆ : O₆

1 : 6

5.3 : 6*5.3 = 31.8 mol

Mass of oxygen:

Mass = number of moles * molar mass

Mass = 31.8 mol * 32 g/mol

Mass = 1017.6 g