Write a balanced equation for the dissolution of sodium carbonate (Na2CO3) in water. Find the number of moles of Na + produced when 0.207 mol of sodium carbonate dissolves.

in the presence of water H2O

Na2CO3 (S) - -> 2Na + (aq) + (CO3) 2 - (aq)

One mole of sodium carbonate produces two moles of Na + ions

Therefore 0.207 moles produces 0.414 moles of Na + ions

= 0.414 moles of Na + ions

Explanation:

In water

Na2CO3 - -> 2Na + (aq) + (CO3) 2 - (aq)

In a limited reaction, the carbonate ion reacts with the water molecules as follows

(CO3) 2 - (aq) + H2O←→HCO3 - (aq) + OH - (aq)

sodium carbonate or soda ash dissolves in water to give 2 sodium cations and one carbonate anion