What is the mass in AMU of 8.441 moles of lead two oxide? Show your work

1.1346 * 10²⁷ amu

Explanation:

Given dа ta:

Number of moles of lead (II) oxide = 8.441 mol

Mass of lead (II) oxide = ?

Solution:

Formula:

Number of moles = mass / molar mass

Molar mass of lead (II) oxide = 223.2 g/mol

Now we will put the values:

8.441 mol = Mass / 223.2 g/mol

Mass = 8.441 mol * 223.2 g/mol

Mass = 1884 g

Gram to AMU:

One gram = 6.022 * 10²³ amu

1884 * 6.022 * 10²³

1.1346 * 10²⁷ amu