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21 November, 10:47

When a 0.089M aqueous solution of a certain acid is prepared, the acid is 12.% dissociated. Calculate the pH of the solution. Round your answer to 2 decimal places.

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  1. 21 November, 12:08
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    pH = 1.98

    Explanation:

    Given a general acid dissociation:

    HA + H₂O ⇆ H₃O⁺ + A⁻

    The pH is - log[ H₃O⁺ ]

    Therefore we need to determine [ H₃O⁺ ] to answer this question, and we should use the data of % dissociation of the acid.

    Percent dissociation is

    % dissociation = [ H₃O⁺ ] / [ HA ]₀ x 100

    where [ HA ]₀ is the original acid concentration, so we can calculate [ H₃O⁺ ], and then the pH.

    12 = [ H₃O⁺ ] / 0.089 M ⇒ [ H₃O⁺ ] = (12 x 0.089 / 100) M

    = 1.07 x 10⁻² M

    and pH = - log (1.07 x 10⁻²) = 1.98
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