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6 December, 06:37

What is the concentration of magnesium bromide, in ppm, if 133.4 g MgBr2 dissolved in 1.84 L water. Then solve for the bromine concentration in ppm

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  1. 6 December, 07:47
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    Answer: 0.0725ppm

    Explanation:

    133.4g of MgBr2 dissolves in 1.84L of water.

    Therefore Xg of MgBr2 will dissolve in 1L of water. i. e

    Xg of MgBr2 = 133.4/1.84 = 72.5g

    The concentration of MgBr2 is 72.5g/L = 0.0725mg/L

    Recall,

    1mg/L = 1ppm

    Therefore, 0.0725mg/L = 0.0725ppm
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