a 25.0mL sample of ammonium nitrate solution produces a 0.186 M solution when diluted with 50.0mL of water. what is the molarity of the stock solution

C₁ = 0.558 M

Explanation:

Given dа ta:

Volume of concentrated solution = V₁ = 25 mL

Molarity of concentrated solution = C₁ = ?

Volume of diluted solution = V₂ = 50mL + 25 mL = 75 mL

Molarity of diluted solution = C₂ = 0.186 M

Solution:

Formula:

C₁V₁ = C₂V₂

Volume of concentrated solution = V₁

Molarity of concentrated solution = C₁

Volume of diluted solution = V₂

Molarity of diluted solution = C₂

Now we will put the values in formula:

C₁V₁ = C₂V₂

C₁ * 25 mL = 0.186 M * 75 mL

C₁ * 25 mL = 13.95 M. mL

C₁ = 13.95 M. mL/25 mL

C₁ = 0.558 M