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17 August, 14:10

What is the minimum number of moles of sodium borohydride required to fully reduce 0.55 grams of benzophenone? Enter only the number with two significant figures.

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  1. 17 August, 15:57
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    see explanation below

    Explanation:

    In this case, is pretty easy. This is a reduction reaction to form the respective alcohol.

    Now for each mole of benzophenone that it's present, reacts with 1 mole of Sodium borohydryde, so, all we need to do, is to calculate the moles of benzophenone presents and these, would be the same moles of NaBH4 so:

    moles Benzophenone : m/MM

    The molar mass of benzophenone reported is 182.22 g/mol so:

    moles Benzophenone = 0.55/182.22 = 3.02x10⁻³ moles

    so the moles of NaBH₄ = 3.02x10⁻³ moles
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