N2 (g) + 3H2-> 2NH3 (g) How many grams of ammonia (NH3) can be produced from the reaction of 28.0 g of N2 and 25.0 g of H2?

34 g of NH₃ were produced in the reaction

Explanation:

N₂ (g) + 3H₂ (g) → 2NH₃ (g)

Moles of N₂ → 28 g / 28 g/m = 1 mol

Moles of H₂ → 25g / 2 g/m = 12.5 moles

Clearly, the limiting is the nitrogen.

1 mol of N₂ produced 2 moles of ammonia

So, If I have 1 mol, I'll produce the same amount

2 moles of NH₃ = Mol. Molar mass

2 m. 17 g/m = 34 g