Which equation is set up correctly to determine the volume of a 3.2 mole sample of oxygen gas at 50 degrees celcius and 101.325 kPa

Ideal gas equation.

Explanation:

Given that:

Pressure = 101.325 kPa

Also, P (kPa) = 1 / 101.325 atm

So, pressure = 1 atm

Temperature = 50°C

The conversion of T (°C) to T (K) is shown below:

T (K) = T (°C) + 273.15

So,

T = (50 + 273.15) K = 323.15 K

Volume = ?

n = 3.2 mole

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L. atm/K. mol

Applying the equation as:

1 atm * V = 3.2 mol * 0.0821 L. atm/K. mol * 323.15 K

⇒V = 84.89 L