I have a balloon that can hold 125,000 mL of air. If I blow up this balloon with 3 moles of oxygen gas at a

pressure of 1 atmosphere, what is the temperature of the balloon? Provide your final answer in degrees

Celsius. Show all your work for full credit.

234.35 °C

Explanation:

Given dа ta:

Volume of balloon = 125000 mL

Moles of oxygen = 3 mol

Pressure = 1 atm

Temperature = ?

Solution:

Formula:

PV = nRT

P = Pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

Volume of balloon = 125000 mL * 1 L / 1000 mL

Volume of balloon = 125 L

Now we will put the values:

Ideal gas constant = R = 0.0821 atm. L/mol. K

PV = nRT

T = PV/nR

T = 1 atm * 125 L / 0.0821 atm. L/mol. K * 3 mol

T = 125 / 0.2463 / K

T = 507.5 K

K to °C

507.5 K - 273.15 = 234.35 °C