A mixture of 50.0ml of ammonia gas and 60.0ml of oxygen gas reacts. If all the gases are at the same temperature and pressure, and the reaction continues till one of the gases is completely consumed. What volume of steam is produced if the other product is nitric oxide gas

The volume of steam produced is 72 ml

Explanation:

We need to first write the balanced equation for the reaction between Ammonia and oxygen.

The balanced equation is;

4NH₃ (g) + 5O₂ (g) → 4NO (g) + 6H₂O (g)

Remember the Gay-lussac's law of combining gases;

At constant pressure and temperature, gases react bearing a simple ratio to one another.

In this case;

From the equation the ratio of the reactants and products will be;

4V: 5V: 4V: 6V

We are given, 50 ml of NH₃ and 60 ml of Oxygen

Assuming all the volume of oxygen (60 ml) was completely consumed, then we can use the simple ratios to find the volume of the other reactant consumed and the volume of reactants.

Volume of O₂ = 60 ml (completely consumed)

The volume of Ammonia = (60/5) * 4

= 48 ml

Therefore; 48 ml of NH₃ was consumed and 2 ml NH₃ remained

The volume of H₂O (steam produced)

The ratio of O₂ to H₂O is 5: 6

Therefore;

Volume of steam = (60/5) * 6

= 72 ml

Therefore; the volume of steam produced is 72 ml