4. A sample of gas occupies a volume of 80. OmL at a pressure of 0.50 atm and a temperature of

0.0°C. What will its volume be at a pressure of 1.50 atm and a temperature of 50.0°C?

The volume will be 31, 55 ml

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. We convert the unit Celsius into Kelvin:

0 ° C = 273K, 50 ° C = 273 + 50 = 323K

(P1x V1) / T1 = (P2xV2) / T2

(0,5atm x 80ml) / 273K = (1,5 atmxV2) / 323K

0,147 atmx ml/K = (1,5 atmxV2) / 323K

V2 = (0,147 atmx ml/Kx 323K) / 1,5atm = 31,55 ml