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20 September, 17:52

Find the mass of AlCl3 that is produced when 25.0 grams of Al2O3 react with excess HCl according to the following equation.

Al2O3 (s) + 6HCl (aq) → 2AlCl3 (aq) + 3H2O (l)

Group of answer choices

72.9 g

155 g

65.4 g

16.3 g

32.6 g

+2
Answers (1)
  1. 20 September, 19:10
    0
    Mass = 65.4 g

    Explanation:

    Given dа ta:

    Mass of Al₂O₃ = 25 g

    Mass of AlCl₃ = ?

    Solution:

    Chemical equation:

    Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O

    Number of moles of Al₂O₃:

    Number of moles = mass / molar mass

    Number of moles = 25 g / 101.96 g/mol

    Number of moles = 0.2452 mol

    Now we will compare the moles of Al₂O₃ and AlCl₃.

    Al₂O₃ : AlCl₃

    1 : 2

    0.2452 : 2*0.2452 = 0.4904 mol

    Mass of AlCl₃:

    Mass = number of moles * molar mass

    Mass = 0.4904 mol * 133.34 g/mol

    Mass = 65.4 g
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