Ask Question
9 November, 09:58

A 455 g piece of bopper tubing is heated to 89.5 C and placed in an insulated vessel containing 159 g of water at 22.8 C. Assuming no loss of water and a heat capacity of 10. J/K for the vessel, what is the final temperature (c of copper = 0.387 J/g*K) ?

+5
Answers (1)
  1. 9 November, 11:15
    0
    The final temperature of the setup = 36.6°C

    Explanation:

    Let the final temperature of the setup be T

    Heat lost by the copper tubing = Heat gained by water and the vessel

    Heat lost by the copper tubing = mC ΔT = 455 * 0.387 * (89.5 - T) = (15759.61 - 176.1T) J

    Heat gained by water = mC ΔT = 159 * 4.186 * (T - 22.8) = (665.6T - 15175.1) J

    Heat gained by vessel = c ΔT = 10 * (T - 22.8) = (10T - 228) J

    Heat lost by the copper tubing = Heat gained by water and the vessel

    (15759.61 - 176.1T) = (665.6T - 15175.1) + (10T - 228)

    851.7 T = 31162.71

    T = 36.6°C
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 455 g piece of bopper tubing is heated to 89.5 C and placed in an insulated vessel containing 159 g of water at 22.8 C. Assuming no loss ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers