Cindy made tea. She started with 300 grams of water at 20 degrees Celsius. She transferred 18,000 calories to the water. What was the final temperature of the water?

Question

Chemistry

Acevedo

26 October, 06:18

Cindy made tea. She started with 300 grams of water at 20 degrees Celsius. She transferred 18,000 calories to the water. What was the final temperature of the water?

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Answers (1)

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Samson Peck · Answer 1

T final = 80°C

Explanation:

Q = mCpΔT

∴ Q = 18000 cal

∴ m H2O = 300 g

∴ Cp H2O (15°C) = 0.99795 cal/g. K ≅ 1 cal/g. K

∴ T1 = 20°C = 293 K

∴ T2 = ?

⇒ 18000 cal = (300 g) (1 cal/g. K) (T2 - 293 K)

⇒ (18000 cal) / (300 cal/K) = T2 - 293 K

⇒ T2 = 293 K + 60 K

⇒ T2 = 353 K (80°C)