As a result of the interaction of 22 g of higher oxide of the element of the main subgroup of group IV with water, 31 g of acid was formed. Set the name of an unknown chemical element.

Carbon (C)

Explanation:

Because the element is the element of the main subgroup of group IV, it has oxidation number + 4 in the oxide, and oxide formula is EO2.

reaction:

EO2 + H2O - --> H2EO3

from reaction 1 mol 1 mol 1 mol

31 g acid - 22 g oxide = 9 g water

M (H2O) = 18 g/mol

9g * 1 mol/18 g = 0.5 mol H2O

As we see from reaction molar ratios EO2 : H2O : H2EO3 = 1 : 1 : 1,

so if we have 0.5 mol H2O, we also have 0.5 mol EO2.

0.5 mol EO2 has mass 22 g.

Molar mass (EO2) = mass / number of moles = 22 g / 0.5 mol = 44 g/mol

Molar mass (EO2) = M (E) + 2M (O) = 44 g/mol

M (E) + 2 * 16 g/mol = 44 g/mo

M (E) = 44-32 = 12 g/mol

Molar mass 12 g / mol is molar mass of carbon.

So, element is carbon (C).