Ask Question
25 November, 23:36

The specific heat capacity of zinc is 0.386 J/g ºC. How many joules would be released when 267 grams of zinc at 96.0 ºC were cooled to 28.0 ºC?

*Answer with a whole number*

Q = mcΔt

+1
Answers (1)
  1. 25 November, 23:46
    0
    70008.216 J

    Explanation:

    The following data were obtained from the question:

    Specific heat capacity (C) = 0.386 J/gºC

    Mass (m) = 267 g

    Initial temperature (T1) = 96.0ºC

    Final temperature (T2) = 28.0ºC

    Change in temperature (ΔT) = T1 - T2 = 96 - 28 = 68°C

    Heat (Q) = ... ?

    The heat released can be obtained as follow:

    Q = MCΔT

    Q = 267 x 0.386 x 68

    Q = 70008.216 J

    Therefore, the heat released is 70008.216 J
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The specific heat capacity of zinc is 0.386 J/g ºC. How many joules would be released when 267 grams of zinc at 96.0 ºC were cooled to 28.0 ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers