Calculate the volume in liters of a barium acetate solution that contains of barium acetate. Be sure your answer has the correct number of significant digits.

1.09 L

Explanation:

There is some info missing. I think this is the original question.

Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.

The molar mass of barium acetate is 255.43 g/mol. The moles corresponding to 100 grams are:

100 g * (1 mol/255.43 g) = 0.391 mol

0.391 moles of barium acetate are contained in an unknown volume of a 0.360 mol/L barium acetate solution. The volume is:

0.391 mol * (1 L/0.360 mol) = 1.09 L

The volume of the solution is 1.09 L

Explanation:

Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.

Step 1: Data given

Molarity of the barium acetate = 0.360 M

Mass of barium acetate = 100 grams

Molar mass barium acetate = 255.43 g/mol

Step 2: Calculate moles of barium acetate

Moles = mass / molar mass

Moles = 100.0 grams / 255.43 g/mol

Moles = 0.3915 moles barium acetate

Step 3: Calculate volume of solution

Molarity = moles / volume

Volume = moles / molarity

Volume = 0.3915 moles / 0.360 M

Volume = 1.0875 L ≈ 1.09 L

The volume of the solution is 1.09 L