Ask Question
15 March, 16:09

The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.42*10-4s-1 at a certain temperature. What is the half-life for this reaction? How long will it take for the concentration of SO2Cl2 to decrease to 25% of its initial concentration? If the initial concentration of SO2Cl2 is 1.00 M, how long will it take for the concentration to decrease to 0.78 M? If the initial concentration of SO2Cl2 is 0.150 M, what is the concentration of SO2Cl2 after 2.00*102s? After 5.00*102s?

+5
Answers (1)
  1. 15 March, 16:56
    0
    a) Half life of the decomposition = 4951.1 s ≈ 4950 s

    b) Time it will take for the concentration of SO₂Cl₂ to decrease to 25% of its initial concentration = 9900 s

    c) If the initial concentration of SO₂Cl₂ is 1.00 M, time it will take for the concentration to decrease to 0.78 M is 1775s

    d) If the initial concentration of SO₂Cl₂ is 0.150 M, the concentration of SO₂Cl₂ after 2.00*10² s is 0.146 M

    e) If the initial concentration of SO₂Cl₂ is 0.150 M, the concentration of SO₂Cl₂ after 2.00*10² s is 0.1398 M

    Explanation:

    Let C₀ represent the initial concentration of SO₂Cl₂

    And C be the concentration of SO₂Cl₂ at anytime.

    a) Rate of a first order reaction is represented by

    dC/dt = - KC

    dC/C = - kdt

    Integrating the left hand side from C₀ to C₀/2 and the right hand side from 0 to t (1/2) (where t (1/2) is the radioactive isotope's half life)

    In [ (C₀/2) / C₀] = - k t (1/2)

    In (1/2) = - k t (1/2)

    - In 2 = - k t (1/2)

    t₍₁,₂₎ = (In 2) / k

    t₍₁,₂₎ = (In 2) / (1.4 * 10⁻⁴)

    t₍₁,₂₎ = 4951.1 s

    b) dC/C = - kdt

    Integrating the left hand side from C₀ to C and the right hand side from 0 to t

    In (C/C₀) = - kt

    C/C₀ = e⁻ᵏᵗ

    C = C₀ e⁻ᵏᵗ

    C = 25% of C₀ = 0.25C₀

    0.25C₀ = C₀ e⁻ᵏᵗ

    e⁻ᵏᵗ = 0.25

    - kt = In 0.25

    - kt = - 1.386

    t = 1.386 / (1.4 * 10⁻⁴) = 9900 s

    c) C = C₀ e⁻ᵏᵗ

    C = 0.78 M; C₀ = 1.00 M

    0.78 = 1 e⁻ᵏᵗ

    e⁻ᵏᵗ = 0.78

    - kt = In 0.78

    - kt = - 0.2485

    t = 0.2485 / (1.4 * 10⁻⁴) = 1775 s

    d) C = C₀ e⁻ᵏᵗ

    C₀ = 0.150 M, t = 2 * 10² s = 200 s

    C = C₀ e⁻ᵏᵗ

    e⁻ᵏᵗ = e^ (-1.4 * 10⁻⁴ * 200) = 0.972

    C = 0.15 * 0.972 = 0.146 M

    e) C = C₀ e⁻ᵏᵗ

    C₀ = 0.150 M, t = 5 * 10² s = 500 s

    C = C₀ e⁻ᵏᵗ

    e⁻ᵏᵗ = e^ (-1.4 * 10⁻⁴ * 500) = 0.9324

    C = 0.15 * 0.9324 = 0.1398 M
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.42*10-4s-1 at a certain temperature. What is the ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers