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6 June, 06:17

assume that you used a 0.660 g piece of pure aluminum in the synthesis of alum and obtained a 63.5% yield of alum. How many grams of alum did you obtain?

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  1. 6 June, 08:47
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    1.015g

    Explanation:

    From the question,

    Mass of Al used = 0.660g

    The percentage yield = 63.5%

    Mass of Alum used = y

    To find the mass of Alum used, do the following:

    %yield = Mass of Al / Mass and Alum

    65% = 0.660/y

    65/100 = 0.660/y

    Cross multiply

    65 x y = 0.660x100

    Divide both side by 65

    y = (0.660x100) / 65

    y = 1.015g

    The mass of alum obtained is 1.015g
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